言語処理100本ノック 2020「49. 名詞間の係り受けパスの抽出」
問題文
問題の概要
問題文に提示された仕様に従って出力します。第5章は2015年版と同様なので、先駆者のコード*1を流用しつつ実装しました。
class Morph: def __init__(self, dc): self.surface = dc['surface'] self.base = dc['base'] self.pos = dc['pos'] self.pos1 = dc['pos1'] class Chunk: def __init__(self, morphs, dst): self.morphs = morphs # 形態素(Morphオブジェクト)のリスト self.dst = dst # 係り先文節インデックス番号 self.srcs = [] # 係り元文節インデックス番号のリスト def parse_cabocha(block): def check_create_chunk(tmp): if len(tmp) > 0: c = Chunk(tmp, dst) res.append(c) tmp = [] return tmp res = [] tmp = [] dst = None for line in block.split('\n'): if line == '': tmp = check_create_chunk(tmp) elif line[0] == '*': dst = line.split(' ')[2].rstrip('D') tmp = check_create_chunk(tmp) else: (surface, attr) = line.split('\t') attr = attr.split(',') lineDict = { 'surface': surface, 'base': attr[6], 'pos': attr[0], 'pos1': attr[1] } tmp.append(Morph(lineDict)) for i, r in enumerate(res): res[int(r.dst)].srcs.append(i) return res def convert(s): pl, nl = [], [c for c in s if '名詞' in [m.pos for m in c.morphs]] for i in range(len(nl) - 1): st1 = [''.join([m.surface if m.pos != '名詞' else 'X' for m in nl[i].morphs])] for e in nl[i + 1:]: dst, p = nl[i].dst, [] st2 = [''.join([m.surface if m.pos != '名詞' else 'Y' for m in e.morphs])] while int(dst) != -1 and dst != s.index(e): p.append(s[int(dst)]) dst = s[int(dst)].dst if len(p) < 1 or p[-1].dst != -1: mid = [''.join([m.surface for m in c.morphs if m.pos != '記号']) for c in p] pl.append(st1 + mid + ['Y']) else: mid, dst = [], e.dst while not s[int(dst)] in p: mid.append(''.join([m.surface for m in s[int(dst)].morphs if m.pos != '記号'])) dst = s[int(dst)].dst ed = [''.join([m.surface for m in s[int(dst)].morphs if m.pos != '記号'])] pl.append([st1, st2 + mid, ed]) return pl filename = 'ch05/ai.ja.txt.cabocha' with open(filename, mode='rt', encoding='utf-8') as f: blocks = f.read().split('EOS\n') blocks = list(filter(lambda x: x != '', blocks)) blocks = [parse_cabocha(block) for block in blocks] for b in blocks: pl = (convert(b)) for p in pl: if isinstance(p[0], str): print(' -> '.join(p)) else: print(p[0][0], ' -> '.join(p[1]), p[2][0], sep=' | ')